Common misconceptions

Common mistake
Wrong: A reaction is nonspontaneous if ΔH is positive, regardless of the TΔS term.
Right: Spontaneity is determined by ΔG = ΔH − TΔS; a large positive TΔS can make ΔG negative even when ΔH is positive.
ΔH is only one component of ΔG. The full equation is ΔG = ΔH − TΔS, so a reaction with positive ΔH can absolutely be spontaneous if TΔS is large enough to make ΔG negative — this happens with entropy-driven processes like protein unfolding or some dissolution reactions. Never call a reaction nonspontaneous based on ΔH alone without checking what the entropy term contributes. On the MCAT, if you see a positive ΔH and large positive ΔS at high temperature, ΔG will be negative and the reaction is spontaneous.
Common mistake
Wrong: When products are low and reactants are high (low Q), ΔG becomes more positive (less favorable).
Right: Low Q means the reaction is far from equilibrium in the forward direction, making ΔG more negative and the reaction more spontaneous.
When Q is low (products scarce relative to reactants), the system is far from equilibrium in the forward direction — the reaction has a strong thermodynamic 'drive' to produce more products. This makes ΔG more negative, not more positive. The math confirms it: ΔG = ΔG° + RT ln Q, and a low Q gives a very negative RT ln Q term that pulls ΔG down. Think of it this way: the reaction 'wants' to move toward equilibrium, and if you're nowhere near equilibrium with excess reactants, the forward reaction is highly favored.
Common mistake
Wrong: ΔG° and ΔG are interchangeable and both describe spontaneity under actual cellular conditions.
Right: ΔG° describes spontaneity only at standard conditions (1 M, 25°C); actual ΔG depends on real concentrations via ΔG = ΔG° + RT ln Q.
ΔG° is a constant for a given reaction at 25°C, 1 M concentrations, and 1 atm — conditions that essentially never exist inside a cell. Actual ΔG depends on real concentrations through the RT ln Q term and will be different from ΔG° whenever Q ≠ 1. Cells exploit this constantly: they maintain low product and high reactant concentrations to keep ΔG negative even when ΔG° is mildly positive. Always ask yourself which value a question is giving you or asking about — confusing the two leads to wrong conclusions about whether a reaction actually proceeds in vivo.
Common mistake
Wrong: Coupling an unfavorable reaction to ATP hydrolysis changes the ΔG° of the unfavorable reaction itself.
Right: Coupling works by summing the ΔG values of both reactions; the individual ΔG° values are unchanged, but the net ΔG becomes negative.
Coupling does not alter the ΔG° of any individual reaction — those values are fixed thermodynamic constants. What coupling does is add the ΔG values of two reactions together, so if ATP hydrolysis releases −30 kJ/mol and the endergonic reaction costs +20 kJ/mol, the net ΔG is −10 kJ/mol and the combined process is spontaneous. This only works because the reactions share a common intermediate (e.g., a phosphorylated substrate), so they are chemically linked and can be treated as a single net reaction. The intrinsic energetics of each step are unchanged — you're just harnessing one to drive the other.
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What the exam tests

  1. Identify whether a reaction is spontaneous, nonspontaneous, or at equilibrium based on the sign and magnitude of ΔG — and distinguish between standard free energy (ΔG°) and actual free energy (ΔG) under real conditions.
  2. Explain mechanistically how coupling an endergonic reaction to ATP hydrolysis (or another exergonic reaction) produces a net negative ΔG, without confusing this with a change in the intrinsic ΔG° of either individual reaction.
  3. Calculate or estimate ΔG using ΔG = ΔG° + RT ln Q, and correctly predict how shifts in reactant or product concentrations (Q relative to K) push ΔG more negative or more positive.
  4. Apply general chemistry thermodynamic principles — especially ΔG = ΔH − TΔS — to biological contexts, recognizing that enthalpy alone does not determine spontaneity and that entropy contributions matter.

Can you avoid these mistakes?

A reaction has ΔG° = +12 kJ/mol. Under cellular conditions, the ratio of reactants to products is very high (Q << K). Is ΔG likely positive or negative? What does this tell you about whether the reaction proceeds?
ATP hydrolysis has ΔG° ≈ −30 kJ/mol. A biosynthetic reaction has ΔG° = +18 kJ/mol. If these reactions are coupled through a shared intermediate, what is the net ΔG°, and is the coupled process thermodynamically favorable?
A reaction is endothermic (ΔH = +40 kJ/mol) but occurs spontaneously at high temperature. What must be true about ΔS, and how does increasing temperature affect ΔG for this reaction?
A biochemistry textbook reports that a metabolic reaction is 'spontaneous under physiological conditions' even though its ΔG° is positive. Explain in one or two sentences how this is possible, using the relationship between ΔG, ΔG°, and Q.

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