Common misconceptions

Common mistake
Wrong: A convex mirror can form a real image when the object is placed beyond the focal point.
Right: Convex mirrors always form virtual, upright, and reduced images regardless of object position.
Convex mirrors are diverging — reflected rays always spread apart, meaning they never actually converge in front of the mirror. A real image requires light rays to physically meet at a point, which can only happen when reflected rays converge. Because convex mirrors only produce diverging reflected rays, the brain has to extend those rays behind the mirror to find where they appear to meet, which is always a virtual image. No object placement changes this fundamental geometry.
Common mistake
Wrong: A positive image distance (di > 0) always means the image is virtual.
Right: For mirrors, a positive di means the image is real and on the same side as the reflected light; a negative di means the image is virtual.
For mirrors, the sign of di tells you which side of the mirror the image is on. A positive di means the image is on the same side as the incoming and reflected light — in front of the mirror — which means light actually converges there, making it a real image. A negative di means the image is behind the mirror where light cannot actually reach, making it virtual. This is the opposite of the intuition some students carry over from lenses, so if you're getting confused, anchor to the physical meaning: real image = light converges = positive di for mirrors.
Common mistake
Wrong: The focal length of a concave mirror is negative.
Right: Concave (converging) mirrors have a positive focal length; convex (diverging) mirrors have a negative focal length.
The sign of focal length follows the same logic as image distance: if the focal point is in front of the mirror (where light actually goes), f is positive. Concave mirrors focus parallel rays to a real focal point in front of the mirror, so f is positive. Convex mirrors have a focal point that exists only as a virtual point behind the mirror, so f is negative. Flipping these signs breaks every calculation you do with the mirror equation, so lock in the physical picture: concave = converging = positive f.
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What the exam tests

  1. Know the image properties (real/virtual, upright/inverted, magnified/reduced) produced by plane, concave, and convex mirrors — and be able to distinguish converging vs. diverging behavior.
  2. Apply the mirror equation (1/f = 1/do + 1/di) and magnification formula (m = -di/do) using correct sign conventions to find image distance, focal length, or magnification.
  3. Predict whether an image will be real or virtual, upright or inverted, and larger or smaller based on where the object sits relative to the focal point and center of curvature.
  4. Read or construct a ray diagram for a mirror setup to locate the image and determine its properties — especially when given an unfamiliar configuration in a passage.

Can you avoid these mistakes?

An object is placed 10 cm in front of a concave mirror with a focal length of 15 cm. Using the mirror equation, find di. Is the image real or virtual? Upright or inverted?
A convex mirror has a focal length of -20 cm. An object is placed 30 cm in front of it. What is the magnification, and what does the sign of m tell you about image orientation?
Without using any equation, explain why a convex mirror cannot form a real image no matter where you place the object. Use the behavior of reflected rays in your answer.
A ray diagram shows two reflected rays diverging after hitting a concave mirror, with their extensions behind the mirror converging at a point. What does this tell you about the object's position relative to the focal point, and what are the image properties?

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