Common misconceptions

Common mistake
Wrong: A catalyst shifts the equilibrium position toward products by lowering the activation energy of the forward reaction more than the reverse.
Right: A catalyst lowers Ea equally for both forward and reverse reactions, increasing both rates proportionally and leaving the equilibrium position unchanged.
A catalyst lowers Ea for both the forward and reverse reactions by exactly the same amount — because it stabilizes the transition state, which is shared by both directions. Since both rate constants increase proportionally, the ratio kforward/kreverse (which equals K) stays constant. The equilibrium position doesn't move; you just reach it faster. If you see a question implying a catalyst 'favors products,' that's a trap.
Common mistake
Wrong: A catalyst is consumed during the reaction because it participates in the mechanism.
Right: A catalyst participates in the mechanism but is regenerated by the end of the reaction and is not consumed overall.
A catalyst does appear in mechanistic steps — it binds to reactants, forms intermediates, and participates in bond-making and bond-breaking. But by the final step of the mechanism, the catalyst is regenerated in its original form. Net consumption is zero. This is why catalysts are written above or below the reaction arrow rather than as reactants. Appearing in a mechanism ≠ being consumed overall.
Common mistake
Wrong: Enzymes only accelerate the forward reaction, driving reactions toward products.
Right: Enzymes lower Ea for both forward and reverse reactions equally; they accelerate approach to equilibrium but do not change the equilibrium constant.
Enzymes are catalysts, and all catalysts lower Ea for both directions equally. An enzyme that catalyzes A → B also accelerates B → A by the same factor. What determines which direction dominates is the thermodynamics (ΔG) and the concentrations of reactants and products — not the enzyme. The enzyme just helps the system reach equilibrium faster; it has no say in where that equilibrium lies.
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What the exam tests

  1. Know the core definition: a catalyst lowers activation energy by providing an alternate pathway, is not consumed overall, and does not change the equilibrium position or equilibrium constant.
  2. Distinguish between homogeneous catalysis (catalyst and reactants in the same phase), heterogeneous catalysis (catalyst in a different phase from reactants), and enzymatic catalysis (protein-based biological catalysts), and recognize examples of each in a passage.
  3. Read reaction-coordinate (energy) diagrams to identify how a catalyst changes Ea for both the forward and reverse reactions, and recognize that the energy difference between reactants and products (ΔG) stays the same.
  4. Connect enzyme function to general catalysis principles: enzymes lower Ea for both forward and reverse reactions equally, speed up approach to equilibrium, and do not alter the equilibrium constant K — then apply this in Michaelis-Menten contexts.

Can you avoid these mistakes?

A reaction has Keq = 0.01 at 37°C. A catalyst is added. What is the new Keq, and how does the catalyst affect the rate of the reverse reaction compared to the forward reaction?
On a reaction coordinate diagram, a catalyst is added and the activation energy drops from 80 kJ/mol to 50 kJ/mol for the forward reaction. What is the new Ea for the reverse reaction if the original reverse Ea was 60 kJ/mol? What stays the same on the diagram?
A student claims that because an enzyme appears in the first step of a proposed mechanism (E + S → ES), it is being consumed. What is wrong with this reasoning, and what additional information from the mechanism would correct it?
Platinum metal catalyzes the reaction H2(g) + O2(g) → H2O(g) by adsorbing the gases onto its surface. What type of catalysis is this, and why? How does this differ from acid-catalyzed ester hydrolysis in aqueous solution?

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