Common misconceptions

Common mistake
Wrong: Reaction orders in the rate law equal the stoichiometric coefficients in the balanced equation.
Right: Reaction orders must be determined experimentally and are independent of stoichiometric coefficients.
The balanced equation tells you the overall stoichiometry of a reaction, not the mechanism. Rate laws reflect the mechanism — specifically the slowest step — which can look completely different from the overall equation. For example, the reaction 2NO2 → 2NO + O2 has a rate law of Rate = k[NO2]^2, which happens to match the coefficient, but that's a coincidence. For most reactions, the orders bear no predictable relationship to stoichiometric coefficients. Always treat orders as unknowns to be solved from experimental data.
Common mistake
Wrong: The rate of disappearance of all reactants is equal regardless of stoichiometry.
Right: Rates of disappearance and appearance must be divided by stoichiometric coefficients to give a single reaction rate (e.g., for A + 2B → C, rate = -d[A]/dt = -½d[B]/dt).
When a reaction consumes species at different rates due to stoichiometry, you can't just set those rates equal. For A + 2B → C, B disappears twice as fast as A — so -d[B]/dt is twice -d[A]/dt. To express one unified 'reaction rate,' you divide each species' rate by its stoichiometric coefficient: rate = -d[A]/dt = -(1/2)d[B]/dt = +d[C]/dt. Think of it like unit conversion — the coefficients are the conversion factors between individual species rates and the overall reaction rate.
Common mistake
Gap: Lacks a systematic procedure for extracting reaction orders from initial-rate data tables
To determine reaction order for a reactant, compare two experiments where only that reactant's concentration changes and calculate the ratio of rates to solve for the exponent.
The method of initial rates is a three-step procedure: (1) Find two experiments where only the reactant you care about changes concentration — everything else stays constant. (2) Write the ratio of the two rate equations; all constant terms cancel, leaving (rate1/rate2) = ([A]1/[A]2)^m. (3) Solve for m algebraically or by inspection. If doubling the concentration doubles the rate, m = 1. If it quadruples the rate, m = 2. If it has no effect, m = 0. Once you have all orders, plug any one experiment's numbers back into the rate law to solve for k.
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What the exam tests

  1. Defining reaction rate as the change in concentration over time, and correctly relating the rates of individual reactants and products using stoichiometric coefficients to express a single overall rate.
  2. Writing and interpreting the rate law (Rate = k[A]^m[B]^n), understanding that the exponents m and n are determined experimentally — not from the balanced equation — and knowing what each term represents.
  3. Using the method of initial rates: given a table of experiments with varying concentrations and measured initial rates, isolating one reactant at a time to calculate its order and then solving for the rate constant k.
  4. Extracting reaction orders and rate constants directly from concentration-versus-rate data tables presented in a passage, including cases where orders are zero, fractional, or non-integer.

Can you avoid these mistakes?

A reaction A + 3B → products has these initial rate data: Exp 1: [A]=0.1M, [B]=0.1M, rate=2×10⁻³ M/s; Exp 2: [A]=0.2M, [B]=0.1M, rate=4×10⁻³ M/s; Exp 3: [A]=0.2M, [B]=0.3M, rate=4×10⁻³ M/s. What is the rate law, and what is k?
For the reaction 2H2 + O2 → 2H2O, a student writes Rate = k[H2]²[O2]. What assumption is this student making, and why might it be wrong?
For the reaction N2 + 3H2 → 2NH3, if H2 is disappearing at 0.06 M/s, what is the rate of disappearance of N2 and the rate of appearance of NH3?
A reaction is found to be zero order in reactant B. If you triple [B] while keeping everything else constant, what happens to the reaction rate? What does this tell you about B's role in the rate-determining step?

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